struct S { int i; int * p;}; main () {S s ; int *p =&s.i ; p[0]=4; p[1]=3; s.p=p; s.p[1]=1;s.p[0]=2struct S { int i; int * p;}; main (){S s ;int *p =&s.i ;p[0]=4;p[1]=3;s.p=p;s.p[1]=1;s.p[0]=2:} 请问程序会在哪一行崩溃?要不然看不懂~@@
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struct S { int i; int * p;}; main () {S s ; int *p =&s.i ; p[0]=4; p[1]=3; s.p=p; s.p[1]=1;s.p[0]=2struct S { int i; int * p;}; main (){S s ;int *p =&s.i ;p[0]=4;p[1]=3;s.p=p;s.p[1]=1;s.p[0]=2:} 请问程序会在哪一行崩溃?要不然看不懂~@@
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请问 scanf(%s%d,s[i].name,&s[i].score); 语句中为什么s[i].name 前可以不加 & s[N] 是结构体数组,定义如下;struct {int num;char name[10];int score;}s[N];
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第一行 type TYPE *creat(int n) { struct stu *head,*pf,*pb; int i; for(i=0;i
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struct S {int a,b;} data [2]={10,100,20,200}; mian() {struct S p=data[1;] printf(%d
,++(p.a)); }
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struct { int i;char str[10];float w;}a1;main(){scanf(%d %s %f,_________);printf(FMAT ,__________);}
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