已知4sin^2 x – 6sinx – cos^2 x + 3cosx = 0 ,求 cos(2x +π/4) / [(1-cos2x)(已知4sin^2 x – 6sinx =cos^2 x -3cosx ,求 cos(2x +π/4) / (1-cos2x)(1-tan2x)的值

来源：学生作业帮助网 编辑：作业帮 时间：2024/09/06 07:44:43
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