P是矩形ABCD内的任意一点,连接PA,PB,PC,PD,得到△PAB,△PBC,△PCD,△PDA设它们的面积分别为S₁,S₂,S₃,S₄,给出如下结论:①S₁+S₂=S₃+S₄②S₂+S₄=S₁+S₃③若
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