设数列{an}的前n项和Sn,且a1=1,Sn=4an+2(n∈N*)1.设bn=an+1-2an,求证:{bn}是等比数列2.设Cn=an/2∧n,求证:{Cn}是等差数列3.求Sn=a1+a2+...+an
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