用三线合一证明等腰三角形已知有△ABC,AD平分∠BAC且交BC于D,DB=DC.求证:△ABC是等腰三角形.证明:∵DB=DC∴AD是△ABC的中线∵AD平分∠BAC且交BC于D∴AD也是△ABC中∠BAC的角平分线∴△ABC是等腰三

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