数列【an】,a1=5,an+1-an=3+4[n-1],求a50
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/08 02:59:45
xN0_8/Ry +E@0Tt6ihJ."%~wg,NjnɟϾb2JK@#KVi|~$>$YBB(/_Oy9c\*a9L"
.lz`KcՆ)`+ft2IjQTsR~oߪymc|Ec-
数列an,a1=4,an+1=5^n*an,求an用累乘法
数列an中,a1=3,an+1=an/2an+1,则an=?
已知数列{an}满足a1=1 an+1=an/(3an+1) 则球an
数列an满足,a1=8且8an+1an-16an+1+2an+5=0
数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an
若数列an满足a1=0.5 an+1=an/5an+1 则an=?an+1为an的后一项
数列 a1=5 an+1=an+4n-1 求an通项公式
数列{an}满足Sn+Sn+1=5/3an+1,a1=4求an
数列【an】,a1=5,an+1-an=3+4[n-1],求a50
数列An,A1=5,An+1=2An+3,求通项公式
数列{an}中,2an*an+1+2an+1-an=0,a1=1,an=?
已知数列{an}中满足(An+1-An)(An+1+An)=16,且a1=1,an
数列{an}中,a1=1/2 3an*an-1+an-an-1=0,通项公式an
数列an中,a1=3,an+1=3an,则an= ,sn=
在数列an中,a1=1,an=3an-1+2则an=
已知数列{an}中,a1=1/2,an+1+3an=0,an=( )
数列{An}中,A1=1,An=0.5An-1 -0.5,则An=_________.
设数列{an}中,a1=2,an+1=an+n+1,则通项an=?