(-1/6x^2y)xxy^2x(-3xyz),3x(x-1)-5x(x+2),(3x+2)(2x-3),因式分解
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(-1/6x^2y)xxy^2x(-3xyz),3x(x-1)-5x(x+2),(3x+2)(2x-3),因式分解
+2y=1 xy+x=1 3x- =5 x2-2=3xxy=1 2x(y+1)=c 2x-y=1 x+y=0 的解谁知道
1.试说明不论x,y取何值时,代数式(xxx+3xxxy-5xyy+6yyy+1)-(2xxx-yyy-2xyy-xxy-2)-(4xxy+7yyy-xxx-3xyy-1)的值是一个常数.2.无论x取何值,代数式-3xx+mx+nxx-x+3的值总是3,试求m,n的值.3.已知y=axxxxx+bxxx+cx-5,当x=-3,y=7,那
x+(9-8-y)=10 y+y-(9-8-y)=2 x-y=xx-9.9x xy=11y-1 y=? x=? x+y-xy=?x+(9-8-y)=10y+y-(9-8-y)=2x-y=xx-9.9xxy=11y-1 y=?x=?x+y-xy=?
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x²/xy-x/y 3x/4x+y - x-2y/4x+y (1-y/y+x)÷x/y²-x²
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x(x-y)2-(y-x)3
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