for(j=i+n+1; j>i; j--)和s[j+1]= s[j]; #include void fun(char *s){int i,j,n;for(i=0; s[i]!='\0'; i++)//s[j+1]= s[j];s[j+1]='*';i=i+1;}}main(){char s[80]="ba3a54cd23a";printf("\nThe original string is :%s\n",s);fun(s);printf("\nThe result is :%s\n",s)

for(j=i+1;j for(j=1;j<=n;j++) { for(i=1;i<m;i++) 数据结构,怎么循环 for (j=i 怎么用lingo求解多目标规划呢,max =@sum(I(i):@sum(J(j):@sum(link(I,J):x(i)*w(j)*p(i,j)/d(i,j))));@for(I(i):@sum(J(j)|w(j)#eq#1:x(i)*p(i,j))>0);@for(I(i):@sum(J(j):x(i)*p(i,j)*c(j))>0);@for(J(j):@sum(link(I,J):x(i)*p(i,j)>=0));@for(l lingo程序求解释~n=@size(cities); min=@sum(link(i,j)|i#ne#j :distance(i,j)*x(i,j)); @sum(cities(i)|i#gt#1 :x(1,i))>=1; @for(cities(i)|i#gt#1:@sum(cities(j)|j#ne#i:x(j,i))=1; @for(cities(j)|j#gt#1#and#j#ne#i:level(j)>=level(i)+x(i,j)-(n-2)*(1-x(i, 2个矩阵相加,For i = 1 To 4For j = 1 To 4c(i,j) = a(i,j) + b(i,j)Picture3.Print c(i,j);If i = 1 And j = 1 ThenMax = c(i,j)ElseIf Max < c(i,j) Then Max = c(i,j):n = i:m = jEnd IfNext jPicture3.PrintNext i这个和For i = 1 To 4For j = 1 To 4c(i,j) for( int i=0,j=1; j < 5; j+=3 ) i=i+j; 为什么等于5 for(i = 1;i < n-1;i ++) for(j = n;j >=i; j --) s; 求s的执行次数,rt 执行下面程序段,语句3的执行次数为for( i = 0; i < n-1; i + +)for( j = n; j > i; j + +)state; if语句用find函数怎么优化,程序如下：for i = 1:mfor j = 1:nif abs(R(i,j)-R1(i,j))>0.05R2(i,j) = R1(i,j)elseR2(i,j) = 0endif abs(G(i,j)-G1(i,j))>0.05G2(i,j) = G1(i,j)elseG2(i,j) = 0endif abs(B(i,j)-B1(i,j))>0.05B2(i,j) = B1(i,j)elseB2(i,j) 这是matlab中水平差分图像的一段代码.谁能告诉我s1((i-1)*n+j)=g1(i,j); %水平差异for i=1:mfor j=1:nif j-1==0g1(i,j)=f(i,j);elseg1(i,j)=abs(f(i,j)-f(i,j-1)); ends1((i-1)*n+j)=g1(i,j);endend for(i=1; i7; j--) { putchar('$'); } putchar(' '); } 向量i(i+j)+j(2j+3j)=? 单片机中定义flag有啥作用flag=1和flag=0都是什么意思void bubble_sort(int array[],int n) { int i,j,flag,temp; for(i = 0; i < n-1; i++) { flag = 1; for(j = 0; j < n-i-1; j++) { if(array[j] > array[j+1]) { temp = array[j]; array[j] = arra for(i=1;i<10;i++){for(j=1;j<=i;j++)解释一下这是什么意思? main() {int i,j,w=0; for(i=4; i; i--) for(j=1;j matlab多元函数求最小值问题matlab求r =1/(9-j)*(i^2+81-18*j+j^2)^(1/2)*(38/5-19/20*fix(j)+1/20*(8-fix(j))^2)+(fix(j)+1-j)/(9-j)*(i^2+81-18*j+j^2)^(1/2)*(9/5-1/10*fix(j))+(j^2-2*j*n+n^2+m^2-2*m*i+i^2)^(1/2)/(j-n)*(-19/20*fix((n*i-m*j)/(i+n-j- 谁能告诉我这两句代码的区别?这两句的区别?1：for(j=i;j>0;j--) if(a[j-1]>v){a[j]=a[j-1];ans++;} 2：for(j=i;j>0 && v