Y=[X+(200/X) ]*2*400+2X*248+200*80 求出Y的最小值?这是高中必修一涉及到的一个应用题的解题答案,请高人指教.

x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 填空：x-y/x+y=( )/x^2-y^2 （x-y)2•(y-x)³(x-y)=? y=x^2-2x（x y=x^2+2x(x 3^x+2x=y,x (x-y) (x-2y)+(x+2y) (x-3y)-2(x-3y) (x-4y)= (x+y)(x-y)+(x-y)平方-(x-y)(3x-y) 其中x=-2 y=3分之一 已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y) {x-y=200 4x+2y=5000 x²-(x-2y)(x+2y)+(x²-y)(y+x²)=? (x-4y)(2x+y)= (x+y)(2x-3y)=? x+y>=2,x-y x+y>=2,x-y y'-2y=(e^x)-x y'+2y/x=x通解 dy/dx=(2x*x*x*y-y*y*y*y)/(x*x*x*x-2x*y*y*y)