(5/2)x+(2/3)y=-10x/3-y/9=1(x-y)/5-(x+y)/2=-1/10(x-y)/7-(x+y)/6=1/2
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已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuaihuajian
5x^3y(x-y)^3-10x^4y^3(y-x)^2因式分解
5x^3y(x-y)^3-10x^4y^3(y-x)^2
x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2
(x+5y)^+(2x+10y)(3x-y)+(3x-y)^
(x+5y)²-(2x+10y)(3x-y)+(3x-y)²
5X^3Y(X-Y)-10X^4Y^3(Y-X)^2因式分解
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
x-y/7 - x+y/10 =1/2 2(x-y)-5(x+y)=3修改、、、、(x-y)/7-(x+y)/10=1/2 2(x-y)-5(x+y)=3
5(x+y)-2x=0 3x-10(x+y)=2
{2X=5(X+Y) 3X-10(X+Y)=2
{2X=5(X+Y)3X-10(X+Y)=2怎么解?