已知数列{a}的前n项和Sn,通项an满足Sn+an=1/2(n^2+3n-2),求通项公式an如题,Sn+an=1/2(n^2+3n-2).(1) S(n-1)+a(n-1)=1/2[(n-1)^2+3(n-1)-2].(2) (1)-(2):an+an-a(n-1)=n+1 2an-a(n-1)=n+1 2an-n-1=a(n-1)即:2(an-n)=a(n-1)-(n-1) 即:(an-n)/[a(n-

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已知数列{a}的前n项和Sn,通项an满足Sn+an=1/2(n^2+3n-2),求通项公式an如题,Sn+an=1/2*(n^2+3n-2).(1) S(n-1)+a(n-1)=1/2*[(n-1)^2+3(n-1)-2].(2) (1)-(2):an+an-a(n-1)=n+1 2an-a(n-1)=n+1 2an-n-1=a(n-1)即:2(an-n)=a(n-1)-(n-1) 即:(an-n)/[a(n-

已知数列{a}的前n项和Sn,通项an满足Sn+an=1/2(n^2+3n-2),求通项公式an如题,Sn+an=1/2(n^2+3n-2).(1) S(n-1)+a(n-1)=1/2[(n-1)^2+3(n-1)-2].(2) (1)-(2):an+an-a(n-1)=n+1 2an-a(n-1)=n+1 2an-n-1=a(n-1)即:2(an-n)=a(n-1)-(n-1) 即:(an-n)/[a(n-