x^2-6xy+9y^2-1=
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1-2/x+y=xy,4y+6x=xy.求xy的解?
已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎
4xy-[(x²+5xy-y²)-(3xy-1/2y)]x=3,y=-6
3x^2-xy /9x^2-6xy+y^2,其中x=1/2,y=-2/3
化简求值x-4y/2x-7xy+3y×x-2xy-3y/2x+3xy-2y÷3x-6y/4x-4xy+y,其中:x=1999,y=-1
-3x^2y+6xy^2-9xy=( )(x-2y+3)
x^2-6xy+9y^2-1=
解方程组:xy/x+y=-6(1) 2xy/x+2y=12(2)
(x-2xy)*(-xy+2y*y)-(3x*x-2xy)(x-9xy+6y*y)答案应为-2x-x*x-3x,
[6xy-3(xy-1/2x的平方y]/3xy=?
①(9x²y-6xy²)÷3xy ②(3x²y-xy²+2分之1xy)÷(-2分之1xy)
解方程组:{x²+xy-2y²=0,x²+6xy-9y²=1
[6xy-3(xy-2分之1x^2y]除3xy,其中x=2002,y=2003
[6xy-3(xy-1/2x的平方y]/3xy=?其中x=2008,y=2009
已知x-xy=8,xy-y=-9,求x+y-2xy的值
已知x+y=1,xy=-2,则x²y+xy²-2xy
已知1/x - 1/y = 2,求3x+7xy-3y / 2x-3xy-2y的值1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/71/x-1/y=2到(y-x)/xy=2 是怎么变化的..
若1/x-1/y=2,求3x-2xy-3y/x-xy-y的值3x-2xy-3y/x-xy-y 不好意思,是3x-2xy-3y/x-2xy-y