lim(x→∞)[(x^3+x^2+x^1+1)^(1/3) - x] 的极限.
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 09:11:32
xN@_emۖDw&jv1KT ^c <
vv+xlMDw.s\zLbg{#hQ@8,Qyģ5DȾ1iQyk&ę
XwK*aӼ"-{CSVYúe>qIФ`%Ss=[kP#8q|#kWhaĐ5,]CyŌ[VoCtd62eaWZK2vg?i2͂}#$H&ߕe
h1q]$iNxC"SaD3LL[Fi +0J5kj^RsBIqg4
*[qvt/=87.3h=nEbidk
lim x→∞(2x+1)/(3x-4)
Lim(x→∞)((2x-3k)/2x)-2x= Lim(x→∞)xsin3/x,
求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限
Lim [x^2/(x^2-1)]^x (x→∞)
lim( x→∞)(1+x / x)^3x
lim(1+x/x)2x (x→∞)
( x+3) lim (------------)的x次方 x->∞ ( x-2)
lim xsin(2/x) x→∞
lim(x→∞)(4x^3+2x-1)/(2x^3-3x+1)
lim(x→∞)(2x^3-x^2-3)/(x^3-x+1)
lim(x→∞)(7x^3+4x)/(2x^3-x^2+3)=?
lim(x→∞)[(X^2+2x+5)/(3x^2-x+1) =
lim(x→∞)[(x^3+x^2+x^1+1)^(1/3) - x] 的极限.
lim(x→∞)(x^2+x)/(x^4-3x-1)的极限
lim(x-cosx)/x x→-∞
lim(x→∞)(cos1/x)^x
求极限 lim [(3+x)/(6+x)]^[(x-1)/2]= x→∞求极限 lim [(3+x)/(6+x)]^[(x-1)/2]=x→∞
f(x)=(2+e^x)/1+e^2x)+ | x|sin1/x求 1)lim[x→+∞]f(x); 2)lim[x→-∞]f(x); 3)lim[x→∞]f(x)