when x3+3x2-2x+7 is divided by x+1,the remainder is.
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/29 01:04:17
xRN@Y&2nj;' Kd(
%Q(GP F*!|x_ j%˞s=f!yj(U*$L\ʒ/*ܧ%|*bXL[c6c?n=5.5Mgm?9aˮSE3|@FNHWAܩW凌TMM43\Xȧb?qKA8,N̮
Zs4:vY>>l#~ւH.N9+ +8P|'Ǻ`:ۯ-I#AuX0r"2 ˨
_#R4F3SuKQ/^oꇸ"Cv}qJn#dk*p
when x3+3x2-2x+7 is divided by x+1,the remainder is.
1.证明(8-7x-6x2+x3)+(x3+5x2+4x-1)-(-x2-3x+2x3-3)的值与x无关.快,
求证:无论X取何值下列(8-7X-6X2+X3)+(X3+5X2+4X-1)-(-X2-3X+2X3-3)结果不变
(3X3+5X2+X)/(7X3+5X-4)
6x+5x2-3x3+2x-7x3,其中x=-5
sat 数学level2 题一道the remainder obtained when 3x4+7x3+8X2-2x-3is divided by X+1 IS__ ?a -3B 0C 3D 5E 13
分解因式 x3+x2+x-3 x3-6x2+11x-6 x4+x3-7x2-x+6
x3+3x2+3x+2因式分解
x3-2x2+3x-2
2x3+3x2-4x-1
因式分解x4+x3+2x2-x+3
因式分解(1+x+x2+x3)2-x3
2x3+4x- x2-(x+x2-2x3) ,其中x= -3
求x4+7x3+8x2-13x-5,已知x2+2x=3
若(x-2)(x2+mx+n)=x3+3x2-7x-6,求m、nrt
用基础解系表示线性方程组的全部解(1)【2x1-x2+x3-2x4=1 】(2) 【x1-2x2+x3=-5】 (3) 【x1-x2-x3+x4=0】【-x1+x2+2x3+x4=0 】 【x1+5x2-7x3=2】 【x1-x2+x3-3x4=1】【x1-x2-2x3+2x4=-0.5 】 【3x1+x2-5x3=-8】 【x1-x2-2x
x3 -x2- x- 2 因式分解
若多项式-2x3+5x2+mx-7+3x2+2x不含一次项