1.已知函数y=Asin(ωx+φ)在同一周期内,当x=π(派）/12时,ymax=2,当y=7π/12时,ymin=-2,那么函数的解析式为（ ）.A.y=2sin(2x+π/3) B.y=2sin(2x-π/6) C.y=2sin(2x+π/6) D.y=2sin(2x-π/3) 2.已知1=sin(2π/3+φ),那么φ=?3.函数y=

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