int a,b,c; float l,s_origin; double sqrt; l = a +int a,b,c;float l,s_origin;double sqrt;l = a + b + c;s_origin = l/2 * (l/2 - a ) * (l/2 - b) * (l/2 -c);sqrt = s_origin;scanf = ("%f,%f",&l,&sqrt)printf = ("l= %f, S=%f"l,sqrt);三角形的周长和面
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