cos^2x-sin^2x=COS2X我知道,我想要详细步骤
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cos2x=cos^2x-sin^2x吗?
2(cos?x-sin?x)=2cos2x
cos^2x-sin^2x=COS2X我知道,我想要详细步骤
:求证:(cos^2x-sin^2x)(cos^4x+sin^4x)+1/4sin2xsin4x=cos2x求证:(cos^2x-sin^2x)(cos^4x+sin^4x)+1/4sin2xsin4x=cos2x我算到右边=cos2x(1-sin^2xcos^2x) 接下来该怎么办?
:求证:(cos^2x-sin^2x)(cos^4x+sin^4x)+1/4sin2xsin4x=cos2x求证:(cos^2x-sin^2x)(cos^4x+sin^4x)+1/4sin2xsin4x=cos2x我算到右边=cos2x(1-sin^2xcos^2x) 接下来该怎么办?
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