把函数f(x)=2sin(2x+φ)(0＜φ＜π)的图像向左平移π/6个单位后得到偶函数g(x)的图像.（1）求φ的值（2）求函数h(x)=f(x-π/12)-g(x)的单调增区间

设函数f(x)=sin(2x+φ)(0 函数f(x)=sin(2x+φ)(0 已知函数f(x)=sin(2x+φ) (0 设函数f(x)=2sin(2x-3π/4)+1,把函数y=f(x) 的图象向左平移φ(0 函数f(x)=sin(2x+φ)((|φ| 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 若函数f(x)=2sinωx(0