数列{an},a1=1,3anan-1+an-an-1=0（n≥2）.1、求an；2、若λan+1/an+1≥λ对任意n≥2恒成立,求实数λ的3、设bn=√an,{bn}的前n项和为Tn,求证：Tn＞2/3（根号下3n+1 -1）

数列题难难啊在数列{An}中,A1=1,AnAn+1=3n求An 数列An满足 根号下AnAn+1 +AnAn+2=4根号下AnAn+1 +An+1An+1 +数列An满足根号下AnAn+1 +AnAn+2=4根号下AnAn+1 +An+1An+1 +3根号下AnAn+1 且A1=1 A2=8 求An通项公式 数列An满足 根号下AnAn+1 +AnAn+2=4根号下AnAn+1 +An+1An+1 +3根号下AnAn+1 且A1=1,A2=8求An 数列{an},a1=1,3anan-1+an-an-1=0（n≥2）.求{an}. 数列{An}满足A1=1/3,且An+1+An^3=3An(1+AnAn+1),求数列{An}的通项公式?） 一道高中数学数列题目an+1+anan-1-2an=0 a1=1 求通项 数列an满足a1=2 ,a2=1,且( an-1 -an )/anan-1 =(an -an+1 )/anan+1 (n大于等于2),求a100 = 在数列{an}中,a1=1,3anan-1+an-1=0（n》=2）证明：{1/an}是等差数列.求数列的通项 数列{an}中,a1=1,√an -√an+1=√anan+1 求通项公式an数列{an}中,a1=1,√an - √an+1 = √anan+1 求通项公式an 已知数列{an}满足a1=1,anan+1=2^n,则a9+a10 数列{an}中,a1=1,√an -√an+1=√anan+1 求通项公式an 数列an中,an不等于0,a1=1,而且3anan+1+an+1-an=0,则a10= 数列{an}满足a1=3,an-anan+1=1,An表示{an}前n项之积,则A2013= 已知数列an满足a1=1/2,anan+1=2an-an+1,求ann+1是下角标 已知数列满足a1=1,√an-1 - √an = √anan-1 ,求an= 数列﹛an﹜满足an+1-an=-anan+1,若a1=1,则a5等于 已知数列满足a1=1,根号an-1-根号an=根号anan-1,求an 数列an满足an+1=2an-1且a1=3,bn=an-1/anan+1,数列bn前n项和为Sn.求数列an通项an,