正方形ABCD中,E,F分别在AD,DC上,∠ABE=∠CBF=15°,G是AD上另一点,且∠BGD=120°,连接EF,BG,FG,EF与BG交于点H.求证:BG=EG+FG
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/02 18:32:47
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