已经3x^2-xy+3y^2=20求8x^2+23y^2的最大值.x^2是x的2次方的意思.

来源：学生作业帮助网 编辑：作业帮 时间：2024/09/14 06:53:27
xZ[S+S[ i./[R'vSCXgw%/ $nڟLFO NhBxWR)(f>}>מ㜚\ $S-jsTB#- Ki' I)5{DG9;z3e19&p~9VqV)SCsf^ΗW##SطiK_Bl}e?9 *U;ÂȈU\/ImO؅)LOlev  X=̰]doK}5pyVNԀŋ&|$V0L};gMoyQf%Ѣf|$9h`(?5*#DĞUx$)l:KuY&LE9WGn#U=L(ڞwՅ`Ǡ[L;_MI*ﲥ-V(YGv,YИy3oIS, 3-tWx ?%<-A &Xp[xt3?v͵cYH#[(\_udW8AR ҍs+o3 8 ˫]K2໓ z2$˱8$5aB꒠f>fj,hz*PrңPsZ W֎) L!79FcC[-z? C+5f_[zĪFy5fc:HԁaCswCM}7"^gɨ/ O!u H|y;kZG7A(tϥP%r낞 xC8~p akK@iIgڙ^h`AaIKRsXL_>d% ^KQ5/\ғ&̥ ">2ת1\P 5"N^;c{Qr1u7.GS]tW(r"m&0LM/OFӛ?5IԆ6i YG ْwܫa:ppbHcx=eepjp'DH†&Ϫtzޑڿ%'"n~ҝHܿ vvKc=Z ~+wz(+F(sόvr8e#Q1U zWG8j8f;;Ր`ttuFuJxċ^%"zhgXUUP$tCko{w%{E`^#&?Cڞ){Ӣp;$rMBk~ңVq "LT,@3VD&*?b<2,N޴r3N@,-gda䲕spye"X{Oľ輗ǀL7Zr$׏1Ljp "~t;maA5,?*?ETŞOVn yzi%_*sEzMg_鈰Z_T\?KW^'^^Rf@ *j_~:GTQ83~I8*vNwBu(ji W88)!YYő+gm 29aOIQo%:lg*7{/6d.SV(ʋEyL$[sh >#^+9m`8܀=+'/tSiO4)*pϽ#%0W`16!6V<+.S;kZvL7閟xX/Oz?Wc^J jKϤ69rR `s/Hޏل9-"X=f:VG@W&]jJJ [U%]J:ZsI}mUhhZ(P"5H†a@n|wvz9,]qCxED\3 @0z!MosA),hJ:絕yֺJz=() 2 QDFU]qc-<*ϟ>ã8ܜO3D@WKY6!C슏DJj/]Z̈xDPWG+ iJCrG(.c]v]錨FCr{g8.7Y^B!9d!CSb,HRPi;ҵ?j/
已经3x^2-xy+3y^2=20求8x^2+23y^2的最大值.x^2是x的2次方的意思. 已知xy/x+y=2,求代数式8x-5xy+8y/-x+3xy-y的值 诺x+y=6,xy=4 求(5x-4y-3xy)-(8x-y+2xy) 当x-y=2xy时,求4x-3xy-4y/xy 若1/x-1/y=2,求3x-2xy-3y/x-xy-y的值3x-2xy-3y/x-xy-y 不好意思，是3x-2xy-3y/x-2xy-y 3X^2+XY+Y=15 求XY. 已知x,y为正整数,并且xy+x+y=71,x^2y+xy^2=880,求3x²+8xy+3y² x*x-xy=-3,2xy-y*y=-8,求2x*x-4xy+y*y的值 x+y=8,xy=15,求x^3y+2x^2y^2+xy^3 已知1/x+1/y=8,求2x-3xy+2y/x+2xy+y的值 已知X+Y=3XY,求2X+2Y-XY除以X+Y+2XY的值,要算理.已知X+Y=3XY,求2X+2Y-XY除以X+Y+2XY的值,要算理. 已知:x/y=-2,求x^2-2xy-3y^2/x^-6xy x+y=8,xy=-2,求(5xy+4x+7y)+(6x-3xy)-(4xy-3y)的值 求（3x^+y^-5xy）-【2x^-（-4xy-y^+7x^）】=? 求（3x^+y^-5xy）-【2x^-（-4xy-y^+7x^）】=? 已知2x+xy=10,3y+2xy=6.求4x+8xy+9y=? 已知x^+xy=-5,xy+y^=8,求2x^-xy-3y^的值都是2次 已知xy/x+y=3,求2x-3xy+2y/-x+3xy-y的值