解方程; (-3x)^2-(2x+1)(3x-2)-3(x+2)(x-2)=0 计算 1.已知x^2+2x+y^2-6y+10=0,求x,y的值解方程;(-3x)^2-(2x+1)(3x-2)-3(x+2)(x-2)=0 计算 1.已知x^2+2x+y^2-6y+10=0,求x,y的值 2.(1-2^2分之1)
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