2x+y+z=11,x+2y+z=16,x+y+2z=17如题,求出x.y.
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用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
方程组:{x+y-z=6,x+z=16,x-y+2z=17
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
方程组x+3y-z=17 2x-y+z=16中的y、z同时满足y=z+2,求x、y、z.急!
(x+y-z)^2-(x-y+z)^2=?
(x-y-z)*( )=x^2-(y+z)^2 填空
分解因式:f(x,y,z)=x^2(y-z)+y^2(z-x)+z^2(x-y)
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
x+2y=3x+2z=4y+z 求x:y:z
x+y/2=z+x/3=y+z/4 x+y+z=27
若x+y+z=3y=2z,则x/x+y+z=?
x+y+z=14 7z=x+y+2 x+z=y
x/2=y/3=z/5 x+3y-z/x-3y+z