化简1/2sin^2x[1/tan(x/2)-tan(x/2)]+根号3/2cos2x.

化简(sin^2 x/sin x-cosx)-(sin x+cosx/tan^2 x-1) (1+tan(x))/sin(2x)不定积分 求证：tan x/2=sin x/(1+cos x) 求证：1-sin(x)=cos(x)*tan(x/2) 求∫1／tan^2x+sin^2x dx (sin^x/sinx-cosx)-sinx+cosx/tan^2x-1 2ln|sec X+tan X|=ln|(1+sin x)/(sin x-1)|怎么证 求证：(sin x+cos x)(1-tan x)=(2sin x)/(tan2x) （1-sin x）/cos x 化成用tan表示怎么表示?tan x/2? 化简1/2sin^2x[1/tan(x/2)-tan(x/2)]+根号3/2cos2x. 求证:(sin 2x /(1-cos 2x) )·(sin x /(1+sin x))=tan (π/4-x/2). 化简sin^4x/sinx-cosx - (sinx+cosx)cos^2x/tan^2x-1 已知k=[2(sin x)^2+sin 2x]/(1+tan x),pai/4 化简sin x/(1－cos x)√[(tan x－sin x)（tan）]化简sin x/(1－cos x)√[(tan x－sin x)/（tan x＋sin x）] 求证；1-2sin Xcos X/cos2 X-sin2 X=1-tan X/1+tan X 证明tan^θ-sin^2θ=tan^2θsin^2θ证明（1）tan^θ-sin^2θ=tan^2θsin^2θ（2）sin^4x+cos^4x=1-2sin^2cos^2x（31-tan^2x/1+tan^2x=cos^2x-sin^2x 求证：1-2sinxcosx/cos方x-sin方x=1-tan/+tan 证明tan^2x=2*tan^2y+1,求证sin^2y=2sin^2x-1