float[] X = new float[] { 1,3,8 }; float[] Y = new float[] { 4,6,16 }; int i = 0; float ki;do{ki = (Y[i + 1] - Y[i]) / (X[i + 1] - X[i]);Console.WriteLine("ki={0}",ki);i++;}while (i

float[] X = new float[] { 1,3,8 }; float[] Y = new float[] { 4,6,16 }; int i = 0; float ki;do{ki = (Y[i + 1] - Y[i]) / (X[i + 1] - X[i]);Console.WriteLine(ki={0},ki);i++;}while (i 浮点数转换成整数问题#include int main(){float a;int c;a = 9/(float)10;c = (int)(a*100);printf(%d ,c);return 0;}//结果不是预期的,是怎么回事,要怎么改正要有通用性的//或者说我换一个写法#include int main(){floa C++ pi的定义我定义了类CTextclass CText:public CDraw{...protected:const float pi;public:CText();CText(short ColorPen,short ColorBrush,short LineWide,shortLineType,short Layer,int id_only,BOOL Delete,float StartX,float StartY,float Angle1,floa float x=2 if (x 求x^3-15x^2+16x-80一个实根,下面程序怎么算不出来#include#includefloat f(float x){return ((x-5)*x-16)*x-80;}float xpoint(float x1,float x2){return (x1*f(x2)-x2*f(x1))/(f(x2)-f(x1));}float root(float x1,float x2){float x,y,y1;y1=f(x1);do{ 解方程x *x *x - 5.0 *x *x + 16.0 *x - 80.0 下面是程序,谁给我讲讲原理啊#include #include float f(float x){float y;y = x *x *x - 5.0 *x *x + 16.0 *x - 80.0;return y; }float xpoint(float x1,float x2){float y;y = (x1 *f(x2) -x2 *f(x1))/(f // void fun( float y ,float x[],) { x[0] = x[1] + x[2]; y = y + x[3] ; 合并排序错误 static int n = 10;static float A[] = new float[n];static float B[] = new float[n];public static void mergeSort(float A[],int left,int right ){if(left < right){ int mid = (left + right) / 2;mergeSort(A,left,mid);mergeSort(A,mid + 1, 编写由三角形三边求面积的函数.#includefloat kig(float x, float y,float z);main(){ float s,a,b,c; scanf(%f%f%f,&a,&b,&c); s=kig(a,b,c); printf(s=%f ,kig(a,b,c));}float kig(float x,float y,float z){ float p; p=1/4*(2*x*z+y*y-x*x-z*z); 再输出大于平均数的成绩.#include #define NUM 8float average(float x[]){ float sum;int k; sum=x[0];for(k=1;k fun(float x) { float y; y=3*x-4; return y; }以上函数值的类型为什么是int?怎么不是float呢? (int)(x*1000+0.5)/(float)1000里的(int)和(float)是什么意思啊?float x=5.16894的话,print(%f,+上面的表达式)怎么运算? 关于定积分~错哪儿了?急~# include # define N 100# define F(x) (x)*(x)*(x)float sab(float a,float b){ float h,sum=0; scanf(%f%f,&a,&b); h=(b-a)/N; for(;a c语言的问题,求x^3-5x^2+16x-80的根,我用的弦截法,但是出错#include#includefloat f(float x){float y;y=x*(x*x-5*x+16)-80;return y;}float xpoint(float x1,float x2){float root;root=(f(x2)*x1-x2*f(x1))/(f(x2)-f(x1));return root;}void main() 以下函数值的类型是 fun ( float x ) { float y; y= 3*x-4; return y; } 以下函数值的类型是（ ）.fun ( float x ) { float y; y= 3*x-4; return y; } 以下函数值的类型是fun ( float x ){ float y;y= 3*x-4;return y;} C语言：下面的功能是计算函数F（x,y,z）=（x+y）*（x+y）+（x+y）*（x-y）的值并输出.float f（float,float）；main（）{float x,y,z,sum；scanf（%f%f%f,&x&y&z）;sum=_____________;printf(sum=%f' ,sum);}float f(float a,