已知数列{a n}满足a1=2,a n+1=(3a n—2)/(2a n—1)求:(1)求出a2 a3的值,并求出数列{a n}的通项公式; (2)设bn=an/2n(2n+1),sn为数列{bn}的前n项和,证明sn上面的a n+1是第n+1项 而后的(3a n—2)/
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