有两个二元一次方程组不会解,高手们帮帮忙,写一下详细步骤,谢了!(1)(2x+3y/4)+(2x-3y/3)=7, (2x+3y/3)+(2x-3y/2)=8; (2)x+1/3 =(y-1/2)+(1/6),(2x/3)+(y/2)=5/3.别理解错了啊,我打括号是为了不与别

来源:学生作业帮助网 编辑:作业帮 时间:2024/09/10 03:33:09
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