上海交大2006 结构力学考研,这道题怎么解支座反力?利用MA=0,则16*6+R3*5*6+R2*15+16*3=24*6,化简得R2+2*R3=0利用MB=0,则R1*15=24*9+16*9+R3*15,化简得R1-R3=24利用MC=0,则R1*30+R2*15=24*24+16*6+16*3再或者用Y=0,R1+R2+R3=24

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