已知a>0,数列{an}满足a1=a,an+1=a+1/an,n=1,2,3……（1）已知数列{an}的极限存在且大于0,求A=liman(将A 用a 表示）（2）设bn=an-A ,n=1,2,3……证明：bn+1=(-bn) / A(A+bn)

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