mathematica 解微分方程组的问题,谢谢了R = 0.008;r = 0.0125;Y = 47.0*2.0*Pi;Z = 0.09;m = 0.08;k = 9.0;g = 9.8;f = 0.000586;e = 28;NDsolve[{R^2*y[t]*y'[t] + z[t]*z'[t] == 0, R^2*Y^2 + Z^2 == R^2*(Y[t])^2 + (z[t])^2, 0.5*m*(z'[t])^2 + 0.
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