(1/2+1/3+··1/2010)(1+1/2+1/3··+1/2009)-(1/2+1/3··+1/2009)(1+1/2+1/3··1/2010)等于多少
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(1/2+1/3+··1/2010)(1+1/2+1/3··+1/2009)-(1/2+1/3··+1/2009)(1+1/2+1/3··1/2010)等于多少
2010·(1-1/2)·(1-1/3)·(1-1/4)·…·(1-1/2010)
1、(1+3+5+···+2009+2011)-(2+4+6+···+2010+2012)
(-1乘2)+(-1/2乘3)+·······+(-1/2010乘1/2011)等于
(-1)+2+(-3)+4+······+(-2009)+2010+(-2011)=________________________(注意:
(1)2010×(1-1/2)×(1-1/3)×(1-1/4)×·········×(1-1/2009)×(1-1/2010) 用简便算法 (2)已知 1/3-1/5=1/3*5*2 那么 1/3*5+1/5*7+1、7*9+···+1、19*21(2)已知 1/3-1/5=1/3*5*2 那么 1/3*5+1/5*7+1、7*9+·
计算:(-1)+(+2)+(-3)+(-4)+.+(-99)+(+100)+.+(-2009)+(+2010)快点··········很急
1+1/(1+2)+1/(1+2+3)+·····+1/(1+2+3+·····+n) 求和
(1/2011-1)(1/2010-1)(1/2009-1)···(1/3-1)(1/2-1)
-1*1/2+(-1/2*1/3)+(-1/3*1/4)+···+(-1/2010*1/2011)
计算(1-2分之1)+(2分之1-3分之1)+(3分之1-4分之1)+···+(2009分之1-2010分之1)
秦始皇和汉武帝各自的功劳是?(用1·······2·······3··········来说)
1/(1+2)+1/(1+2+3)+1/(1+2+3+4)+······+1/(1+2+3+······+200)=?
判断下列无穷级数的敛散性(1)1+2+3+···+n+···(2)1/(1·2)+1/(2·3)+···+1/n(/n+1)+···
急·····················1+2+3+...+999=?
计算:(1-1/21)×(1-1/20)×(1-1/19)×(1-1/18)×······(1-1/3)×(1-1/2)(要完整)
2[4/3y—(2/3y—1/2)]=3/4y急·································!1
1 2 3 4 ·····7 ·······10 ········?1 3 5 7 ·····?······?··········290 1 4 9 ·····?······?··········?