tan(a+π/4)=k,则cos2a=
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/28 15:45:08
x}P=0JĦ#($4A"A
&
D\\#KXq
"cԥyLy Iಣ`0Ge:U~H쨊գH?W9ǀ
#ZhZC@l
*5tO8Ң&5F5nQa5\fbHrTvL%
tan(a+π/4)=k,则cos2a=
tan(a+π/4)=k,则cos2a=?
tan(a+π/4)=2,则cos2a+3sin^2a+tan a=
已知tan(π-a)=-1/2,则cos2a=
已知TAN(A+4/π)=2怎cos2A=?
tan(π/4+a)=3,求sin2a-2cos2a
tan(a+π/4)=2cos2a 怎么化简
cos2a/tan(π/4+a),
已知tan(a+派/4)=2,则cos2a=
tan(a+π/4)=2,则(sin2a-cos²a)/(1+cos2a)=?
tan(a+π/4)=2,则cos2a+3sin^2a+tan2a=
tan(a+π/4)=3+2倍根号2,则1-cos2a/sin2a=
已知tan(π/4-a)=-1/2,则cos2a=
若tan(a+3π/4)=2011,则1/cos2a+tan2a=?没思路,
有好评, tan(π/4-A)=3,则cos2A/(1+sin2A)=
已知tan(π/4+a)=3,则2sina*cosa-1-cos2a=?
已知tan(a+π/4)=1/3,则(sina-cosa)^2/cos2a
求证(1+sin2a-cos2a)/(1+sin2a+cos2a)=tan a