y=xarcsin(x/2)+根号(4-x平方),求导数,麻烦写详细点,
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y=xarcsin(x/2)+根号(4-x平方),求导数,麻烦写详细点,
y=xarcsin(x/2)+根号(4-x平方),求导数,麻烦写详细点,
y=(2+cosx)^x+1-x/1+xarcsin根号下1-x^2的导数
y=xarcsin根号下x/(1+x)+arctan根号下x-根号2-根号x求导
求解这个不定积分∫[xarcsin√(x^4+x^2)]+x^2*e^[-(x^3)]dx 上限1,下限-1 原式=∫[xarcsin√(x^4+x^2)]dx+∫x^2*e^[-(x^3)]dx 上限1,下限-1 =0+∫e^[-(x^3)]d(^[-(x^3)](-1/3)为什么分成两个定积分后,第一个定积分等于0呢?
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根号x+y-4加根号x-y-2=0,所以根号xy=?
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