[3x-29/6]-2x-1=0 log（√3/3）（[x]-1)=[x]-6求x的值!以上为数学竞赛题!其中[x]为高斯函数!这是两题，不是一题！到=0为第一题

log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解,求每步详...log(2x)+log(3y)-log(2z) 怎么化简?log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解, log(2)(x)log(2)(4x)-3log(2)(x)-12=0 (log(2)(x))^3-4(log(4)(x))^2+log(16)(x)=0 log(9)x+log(x^2)3=1的解为?原方程可可化为log(3 ²)x+log(x)²3=1 ,∴1/2*log(3)X+1/2*log(x)3=1,∴[log(3)x]²-2log(x)3+1=0,即[log(3)x-1]²=0请问这里的[log(3)x]²-2log(x)3+1=0是怎么推出来的,刚学基础不好, log底数7[log底数3（log底数2X）]=0,那么x^1/2的值是 已知log(2){log(3)[log(4)(x)]}=5^0,则x=? 2 log(3x)= log 4 +log(6-x)怎么求...急 2log∨6x=1-log∨6 3,则x的值是什么 已知log(8)[log(3)X]=0,那么X^(-1/2)= 解[log(x-1)]²+2log(x-1)-3=0 已知log（2）[log（3)(log(4) x)] = log(3) [log(4) (log(2) y)]=0,求x+y的值 log(2x)+log(3y)-log(2z) 怎么化简? log3(x^2-2x-6)=2 log(3x+6)=1+log(x)求解. 1/log（2）x+1/log（3）x+1/log（4）x=1,x=? log(0.5x)(2)-log(0.5x^3)(x^2)=log(0.5x^3)(4) （高一）若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{log(√2)[(√x)/2]}的最大值和最小若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{log(√2)[(√x)/2]}的最大值和最小值,并求此时x的值.rt 解方程3log(x)4+2log(4x)4+3log(16x)4=0 log(X+5)+log(X+2)=1 已知函数f(x)=log.(1-x)+log.(x+3)（0