如果3X+7Y+Z=1,4X+10Y+Z=2006,求X+3/2005X+2005Y+2005Z
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/27 04:20:10
x){ټ9Q:&چ γM@i6Q6IEj/g
如果3X+7Y+Z=1,4X+10Y+Z=2006,求X+3/2005X+2005Y+2005Z
如果,根号x-3+| y-2 |+z^2=2z-1 求 (x+z)^y
若3x+7y+z=5,4x+10y+z=3,则x+y+z=?
4x+y+z=-3 2x+3y-4z=-10 x+2y-z=-1
已知3x+7y+z=315和4x+10y+z=420,求x+y+z
解方程组:3x+7y+z=31.5,4x+10y+z=42求 x+y+z
3x+2y+z=4 x+y+z=10 2x+3y-z=1
{x+y+z=1 {x+3y+7z=2 {x+5y+19z=4
2x+3y+z=8 4x-y-z=10 x+2y-z=1
1.{x:y:z=3:4:5 2x+3y-5z=-142.{x-y-z=-1 3x+5y+7z=11 4x-y+2z=-13.{x+y=1 x+z=0 2x+y+2z=44.{x-y+z=-3 2x-y-z=-2 -3x+y+z=-15.{x-y+z=-3 3x+y-4z=6 2x+y-z=36.{x-2y+5z=16 2x+y-5z=7 2x-y+z=38
谢了3x+7y+z=315 4x+10y+z=4203x+7y+z=3154x+10y+z=420
x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=?
三元一次方程 X-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 X=?Y=?Z=?
已知x、y、z满足{3x+7y+z=5 ,求x+y+z的值 {4x+10y+z=3
已知x,y,z满足3x+7y+z=5 4x+10y+z=3 求x+y+z的值
已知4x-3y-6z=0,x+2y-7z=0,求5x+2y-z/2x-3y-10z
已知,方程组:4x-3y-7z=0 x+2y=10z 则(x-y+z)÷(x+y+z)=——
第1题 {x+2y+3z=4{y+z=1{3x+2z=3 第2题{x+y=7{y+z=10{z+x=9 第3题 {x+2y+z=10{2x+3y-z=2{3x+2y+2z=17