2500(1+x)+2500(1+x)(1+x)=6600求过程2500（1+x）+2500（1+x）（1+x）=6600求解方程具体过程

x/x+(1-x)/x-1/x *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x 七年级下册政治复习提纲(山东人民出版社)第五单元是 青春的脚步 青春的气息别弄错了啊!格式：X X X X X X X X X 1、X X X X X X X X X X.2、X X X X X X X X X.3、X X X X X X X X X X X. (x+1)(x-1)(x-x+1)(x+x+1) 分解因式----（X*X-X)(X*X-X-2)+1 X(X-1)=X 1.1/x|x/(x+1)| x/x-1[1+(x-1/x)] x-1/x÷(x-1/x) 】x(x+1)+x^2(x-1) 1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做 用matlab求解三元二次方程组 ,eq1=(x(1)*exp(x(1)^2/(10000*x(3)) - (29*x(3))/2500 - x(2)^2/(10000*x(3)) + 75979/10000))/(5000*x(3)) eq2=-(x(2)*exp(x(1)^2/(10000*x(3)) - (29*x(3))/2500 - x(2)^2/(10000*x(3)) + 75979/10000))/(5000*x(3))eq3=-exp(x 已知x²+x=1,求x四次方+x³-x²-2x+2005的值应该是求x4次方+2x³-x²-2x+2500的值 (2500/X-10)(X+1)-2500=440 x>1/1-x x+1/x-1 (X + 1) /(x - 1)