设数列An的前n项满足A1=0,An+1+Sn=n2+2n求通项公式其中答案说,因为An+1+Sn=Sn+1 这一步不懂请解释
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设数列{an}满足:a1=1,an+1=3an属于N+.求{an}的通项公式及前n项和Sn
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已知数列{an}满足A1=2,An+1=An - 1/n(n+1) (1)求数列an的通项公式 (2)设{Bn}=nAn*2^n,求数列Bn前n项和SnRT已知数列{an}满足A1=2,An+1=An - 1/n(n+1) (1)求数列an的通项公式(2)设{Bn}=nAn*2^n,求数列Bn前n项和Sn是A(n+1)
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数列an满足a1=1/2 a(n+1)=1/2-an (1)求数列an的通向公式 (2)设数列an的前n项为Sn 证明Sn
【高考】若数列{an}满足,a1=1,且a(n+1)=an/(1+an),设数列{bn}的前n项和为Sn,且Sn=2-bn,求{bn/an}的前...【高考】若数列{an}满足,a1=1,且a(n+1)=an/(1+an),设数列{bn}的前n项和为Sn,且Sn=2-bn,求{bn/an}的前n项和Tn