计算9^[(log3(-2)^2]= 怎么算
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计算9^log3 4+2
计算log3[(9^2 * 27^(1/3))/3^(log3 234)]
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计算9^[(log3(-2)^2]= 怎么算
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2log3^2-log3^(32/9)+log3^8
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log3(2)*log8(9)
2log3 2-log3 32/9+log3 8-3^2+log3 5
2log3 2-log3 32/9+log3 8-3^2+log3 5 明天要交的