数列{an}满足 a1=1,a(n+1)=(n^2+n-λ)an(n=1,2 )λ是常数（Ⅰ）当a2=-1时,求λ及a3的值；（Ⅱ）数列{an}是否可能为等差数列?若可能,求出它的通项公式；若不可能,说明理由；（III）设bn=a(n+1)/an(n∈N+) ,试

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