-..急吖..-..先给着100分..已知a是方程x^2+x-(1/2)=0的一个根,试求代数式[a^3-1]/[a^5+a^4-a^3-a^2]的值..已知A-B=4,且(A+B+1)(A+B-1)=63,化简(A-B)/(2A+2B)-(A^2+B^2)/(A^2-B^2)后,再求其值.若二次三项式(K+1)X^2-2X-1在实数
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