cosπ/5cos2π/5的值等于A.1/4; B.1/2; C2; D4(要演算过程)
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/16 09:02:46
xSN@.MIL$>D]A"{3&A( ( iYN+6`\h{Μ{fkc$; YviazFEҜϲ84OV+$)q/'tkRz=VI !$q@Gx%܄SE1ZI]SکF̼^]|CVA/Pn Iގic`.JGFPMknQ T
8
7MpQ/e^]\
&@NC\ǞX[*Ř-R9IAD!8բYCUMY-UP(w$`h{ߺL{&~
(cosπ/5)(cos2π/5)的值等于
cosπ/5*cos2π/5的值等于
cosπ/5cos2π/5的值等于A.1/4; B.1/2; C2; D4(要演算过程)
cosπ/5*cos2π/5的值等于 A1/4 B1/2 C2 D4
cosπ/5·cos2π/5等于多少?
cosπ/5 乘以cos2π/5等于多少
cosπ/5cos2π/5的值等于 :麻烦过程竖着写 横着写看不懂~最好一步一步写清楚~
求COSπ/5*COS2π/5
cosπ/5×cos2π/5=
COSπ/5乘以COS2π/5
cosπ/5×cos2π/5
cosπ/5cos2π/5
cosπ/5cos2π/5=?
cosπ/5 - cos2π/5 怎样变成 cosπ/5 + cos2π/5rt
[cos2(π/4+a/2)-cos2(π/4-a/2)]/sin(π-a)+cos(3π+a)的值已知sin(π/2+a)=-√5/5,a属于(0,π)
sinα=1/3-cosα,则sin(π/4-α)/cos2α的值等于?
COS2(π-a)等于什么.?
已知cosθ等于负5分之3,且θ属于(π,2分之3π),求cos2分之θ的值值