1:已知x+y=4,xy=-12,求(x-y)^2(平方)和x^3(立方)+y^3(立方)的值.2:若x^2+2x+y^2-6y+10=0,试求x、y的值.3:如果(x^2+px+8)(x^2-3x+q)的结果中不含有x^2和x^3项,试求p、q的值.4:已知3(a^2+b^2+c^2)=(a+b+c),求证a=b=c
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