f(x)=5x^2-4x-3f(x)=-3x^2+5x-8配方
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① f(x)为一次函数,且f[f(x)]=1+4x,求f(x)② f(x)+2f(-x)=3x+x平方 ,求f(x)③ f(x)为一次函数,且f(x+1)+f(x-1)=2x平方-4x+4,求f(x)④ f(2x-1)定义域(-1,5],求f(2-5x)定义域,求f(x)定义域⑤ f(x)定义域[0,2] ,求f(x平方)
f(x+1)+f(x-1)=4x^3-2x求f(x)
数学f(x)=x(x+1)(x+2)(x+3)(x+4)(x+5),求f'(0)=?
已知f(x)=x(x-1)(x-2)(x-3)(x-4)(x-5),则f‘(0)为
f(x+2)>=f(x)+2,f(x+3)
f(x)=5x+3 f(x)=5x f(x)=x+2x+1 f(x)=5x+3 f(x)=5x f(x)=x+2x+1
若函数f(x)满足f(x)+2f(1/x)=5x+4/x,则f(x)=
f(X)=f(X+2)(x
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f(x)=5x^2-4x-3f(x)=-3x^2+5x-8配方
已知f(x)=(x-1)(x-2)(x-3)(x-4)(x-5),则f'(1)=?求过程