SELECT sum(1) FROM table;和SELECT count(1) FROM table;SELECT sum(1) FROM table;----------------累加'1'列的总和;SELECT count(1) FROM table;--------------统计'1'列的总条数;这里总和与总条数有何不同?应该是这样：如果：SE

oracle报错00936 缺失表达式 错误 select t.comcode 组代码,(select y.comcname from cc_company y where y.comcode=t.comcode) 组名称,sum(decode(aa.a3,0,aa.a1,0)) as 零分总量,sum(decode(aa.a3,1,aa.a1,0)) as 一分总量,sum(decode(aa.a3,2 SQL2005 报错 在关键字'group' 附近有语法错误select a,b,sum(x) from (select a,b,'1' as x from aaaunion allselect a,b,'-1' as x from bbb)group by a,b改成下面这样还是同样报错：select a,b,sum(x) from (select a,b,'1' as x from aaa SELECT sum(1) FROM table;和SELECT count(1) FROM table;SELECT sum(1) FROM table;----------------累加'1'列的总和;SELECT count(1) FROM table;--------------统计'1'列的总条数;这里总和与总条数有何不同?应该是这样：如果：SE select count(1) from emp sql函数,select count(A.abc) as sum from A left join B on A.id=B.id where A.abc='1' group by A.abc结果是 sum 234怎么求count(A.abc) as sum 的总数. 我数据库中有status 和value如果status=0 value!=0我sum的时候想统计value如果status为0的value也为0急比如 select t.status,t.value from table_name;status value------------------0 1231 123我想select sum(value) from table_name的 1' union select * from [ADM] union select * Caused by:java.lang.IllegalArgumentException:No positional parameters in query:select sum(case when t.expenseDeatailLine.financeauditmoney>0 then t.expenseDeatailLine.financeauditmoney eles t.expenseDeatailLine.reimbursementamount end ) from TravelEx 有关group by报错,not a GOUP BY expression这条就会报错select acmratt.brcode,sum(acmratt.tdccramt)from acmratt group by 1但是,改成select acmratt.brcode,sum(acmratt.tdccramt)from acmratt group by acmratt.brcode就可以过…… 这是为 请问 select top 1 1 from ... oracle高手进为什么这样差不出值来,数据库中是有值的select wm_concat(decode(a,'01','aa',a)) from (select regexp_substr(t.gwys_1,'[^,]+',1,rownum) a,t.pk_dyccqsfjlb_id id from mchis.jdh_mcheck_first t connect by rownum oracle中sum(Part_Order_Detail.Shipped_Qty)什么意思呀还有怎么写呀,就是select.from.之类的格式 org.hibernate.hql.ast.QuerySyntaxException: unexpected token: * near line 1, column 8* near line 1, column 8 [select * from (select t.*, rownum rn from edu.rjxy.entity.Task t) where rn>=(?-1)*?+1 and rn 有三张不同表,对每一个表的指定一列求和,一次执行这三条语句该怎么写?要求三个结果能显示就行.rt每次都有执行三条下列语句：select sum(column1) from table_a;select sum(column2) from table_b;select sum(co select * from book limit , oracle sum（）函数的问题~在orale11g中,sum（6）表示的不是第六列的总和,应该是什么呢?在emp表中,第六列是工资,select sum(6) from emp;返回的是84.select sum(sal) from emp;返回的是29025. select * from tablename t 表名后面 t 有什么含义 针对这条语句查表时很慢,怎么才能快一些$orderdetail['yk']=$db->execute(select sum(tb_moneychange.changemoneynum) as yk from tb_moneychange where tb_moneychange.orderno in (select tb_moneychange.orderno from tb_moneychange where tb_mo