cos π/15 * cos 2π/15 * cos4π/15 * cos8π/15
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/18 11:51:27
x)K/V8ߠoh b!qL`MR>ZlȲ6P_83O3VȆ$4ii5Q&`LmmAC3C3ioІ$)@b6yvxsnh{l}9Og>7i
ESl`ah
Dhg<ޱ+^6xq=
#3`PT `كhl5@:.\[]\ٔm/nG ^ե4
求问一道高一数学计算题.cos(π/15)cos(2π/15)cos(4π/15)cos(8π/15)
cos π/15 * cos 2π/15 * cos4π/15 * cos8π/15
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
cos(π/17)*cos(2π/17)*cos(4π/17)*cos(8π/17)
cos^2α+cos^2(α+π/3)-cosαcos(α+π/3)化简
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/15)×cos(6pai/15)×cos(7pai/15)求值
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/15)×cos(6pai/15)×cos(7pai/15)求值
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
已知sina=15/17,cosβ= - 5/13,a∈(π/2,π),求cos(a+β),cos(a-β)的值.急用
cos(θ-π/2)等于cos(π/2-θ)
2cos(π/2+a)cos(π-a)化简
计算cos(π/5)cos(2π/5)的值
cos(-x-2π) 和cos(π-x) 化简
Cos(α-π) Cos(α- π/2 )如何化简
化简cos^2(A+15)+cos^2(A-15)-cos30cos2A
为什么cos(θ-2π)=cosθ,