代数式的恒等变形(1).已知x²+y²+z²-2x+4y-6z+14=0,求（x-y-z)＾2010(2)设m、n满足m²n²+m²+n²+10mn+16=0,求m+n的值（3）已知14（a²+b²+c²)=(a+2b+3c)² 求证a:b:c=1:2:3(4)已知实
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