1.绝对值不大于3的所有整数是2.已知m,n互为相反数,p,q互为倒数.a的绝对值为2,求2000分之m+n-2001pq+4分之1a的平方的值.3.1+1+2分之1+1+2+3分之1+1+2+3+4分之1+······+1+2+3+4+····100分之1等于=( )第

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