若2^(2X+3)-2^(2X+1)=48,求X的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/17 11:02:27
x){ѽ(N(BXS0Դ5y)
{lQ_`gCy
h+VK(HPYhn&C3[8Pƴ53~qAb}6`)6 6!RHpV$n[" n#@ q$
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
(x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3)
x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x
X+X+X+(X-1)+(X-2)+(X-3)+(X-4)=10(X-3)+(X-4)
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=?
x^4+x^3+x^2+x+1=0,x^2006+x^2005+x^2004+x^2003+x^2002
若x^3+x^2+x+1=0,求代数式1+x+x^2+x^3+x^4+x^5+...+x^2006+x^2007的值
写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4
若x=π/3,|x+1|+|x+3|+...+|x+13|-|x+2|-|x+4|-...-|x+12|55555555.
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
x^5-x^4+x^3-x^2+x-1
(X+1)X(X+2)X(X+3)=504
(x+1)(x+2)(x+3)(x+4)=24
(x-1)(x-2)(x-3)(x-4)=48
(x+1)(x+2)(x+3)(x+4)=24
x-1+x+2+x/3+4x=77