已知两直线L1:ax-by+4=0,L2:(a-1)x+y+b=0,求分别满足下列条件的a,b (1)直线L1过点(-3,-1),并且直线L1与L2垂直 L1过点(-3,-1),则-3a+b+4=0,得b=3a-4,L1:ax-(3a-4)y+4=0直线L1与直线L2垂直,则a(a-1)-(3a-4)*1=0,得a
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