已知数列{an}满足a1=1,an+a（n+1）=-2n 求证（1）数列{a2n}与{a（2n-1）}均是以2为公差的等差数列；试用n表示和试M=a1a2-a2a3+…+（-1）^(k+1 )*aka(k+1)+...+a(2n-1)a2n-a2na（2n+1)

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